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24p^2+56p-48=0
a = 24; b = 56; c = -48;
Δ = b2-4ac
Δ = 562-4·24·(-48)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7744}=88$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-88}{2*24}=\frac{-144}{48} =-3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+88}{2*24}=\frac{32}{48} =2/3 $
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